35x^2-66x+27=0

Solution for 35x^2-66x+27=0 equation:

35x^2-66x+27=0

a = 35; b = -66; c = +27;
Δ = b2-4ac
Δ = -662-4·35·27
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-24}{2*35}=\frac{42}{70}
=3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+24}{2*35}=\frac{90}{70}
=1+2/7
$